please solve, the above attachment. In the question [(:) the sign represent - ( is to) ] and ans is (ab). Just I need solution
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solving first side,
(1/a+1/b-2c/ab)(a+b+2c)
{(a+b-2c)/ab}(a+b+2c)
let a+b=x &2c=y
1/ab(x+y)(x-y)
1/ab{x²-y²}
put values of x & y
⇒(a+b)²-(2c)²
⇒a²+b²+2ab-4c²⇒(a+b)²-2c²...........(1)
Solving right side,
1/a²+1/b²+2/ab-4c²/a²b²
(a²+b²+2ab)/ab-4c²/a²b²
(a+b)²-(2c/ab)².......................(2)
divide(1) by(2)
you will get ab:1
(1/a+1/b-2c/ab)(a+b+2c)
{(a+b-2c)/ab}(a+b+2c)
let a+b=x &2c=y
1/ab(x+y)(x-y)
1/ab{x²-y²}
put values of x & y
⇒(a+b)²-(2c)²
⇒a²+b²+2ab-4c²⇒(a+b)²-2c²...........(1)
Solving right side,
1/a²+1/b²+2/ab-4c²/a²b²
(a²+b²+2ab)/ab-4c²/a²b²
(a+b)²-(2c/ab)².......................(2)
divide(1) by(2)
you will get ab:1
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