Question

please solve the above both questions please it's urgent ..​

Answer 1

Answer:

here are both of the answers.

hope it helps.

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Explanation:

2. Let us take the velocity of the bus to be v. Also, for our convenience, let the person and a bus start at time t1 o’clock from town A. And let another bus and the person reach town B at time t2 o’clock.

In the direction of motion:

The man meets another bus at time t1+18 min. By the time, he has covered the distance of d1=20km60min×18min=6km. The next bus started at, t1+T min. So, the next bus has travelled this 6 km in ((t1+18)−(t1+T))=18−T min. So ….

(18−T).v=6…………………1st equation

Opposite to the direction of motion:

The man and the bus reach town B at t2 . He met the previous bus at t2−6 min when he was d2=20km60min×6min=2km . And the previous bus started from B at t2−T . So, the previous bus travelled 2 km in time ((t2−6)−(t2−T))=T−6 min. So …..

(T−6).v=2……………………..2nd equation

Solving two equations, we get

T= 9 min and  v=23km/min=2×603km/h=40km/h  

This is the required answer.

Answer 2

Answer:

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