Question

please solve the above it's urgent
both 2 question​

Answer 1

Answer:

Q54 ) Find the value of √248+√52+√144

√248 + √52 + √ 12×12

√248 +√52 +12

√ 248 +√ 64

√248 +√ 8×8

√248 + 8

√ 256

√ 16×16

16 is the correct answer

Q55) Find the value of

(3^-1 + 4^-1 ) ^-1 ÷5^-1

( 1/3 + 1/4 )^-1 ÷1/5

( 4+3 /12 )^-1 ÷1/5

(7 /12 ) ^-1 ÷1/5

12/7 ÷1/5

12/7 ×5

60/7

Answer 2

$\large\mathfrak \pink{Solution:-}$

$1) \sqrt{248 + \sqrt{52 + \sqrt{144} } } \\ \\ \implies \sqrt{248 + \sqrt{52 + 12} } - - ( \sqrt{144} = 12)\\ \\ \implies \sqrt{248 + \sqrt{64} } \\ \\ \implies \sqrt{248 + 8}- - ( \sqrt{64} = 8)\\ \\ \implies \sqrt{256} \\ \\ \implies \: 16$

$\underline \mathbb{ANSWER:-}$

$\\ { \implies\boxed{ \: 16}}$

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$\large\mathfrak \pink{Solution:-}$

$\underline \mathbb{FORMULA:-}$

${a}^{ - 1} = \frac{1}{a}$

$a\div b = a \times \frac{1}{b} = \frac{a}{b}$

$\underline \mathbb{BY \: THE \: PROBLEM:-}$

${( {3}^{ - 1} + {4}^{ - 1})}^{ - 1} \div {5}^{ - 1} \\ \\ \implies \: {( \frac{1}{3} + \frac{1}{4} )}^{ - 1} \div \frac{1}{5} \\ \\ \implies \: { (\frac{4 + 3}{12} )}^{ - 1} \times 5 \\ \\ \implies \: { (\frac{7}{12}) }^{ - 1} \times 5 \\ \\ \implies \: \frac{12}{7} \times 5 \\ \\ \implies \: \frac{60}{7}$

$\underline \mathbb{ANSWER:-}$

$\\ \implies \boxed{ \frac{60}{7} }$