Question

please solve the above numerical​

Answer 1

Answer:

i) Total power = 2780 W

ii) Total energy consumed in one day = 22.24 KW

iii) Energy consumed for the month of November = 667.2 KW

iv) Bill for the month of November if a unit of electricity costs Rs.26 = Rs.17347.2/-

Explanation:

It is given that 5 bulbs of 60 W, 6 fans of 80 W, and 2 air conditioners of 1 KW are used 8 hours daily. Then,

i)  The power consumed by,

5 bulbs of 60 W = $5\times 60=300\ W$

6 fans of 80 W= $6\times 80=480\ W$

2 air conditioners of 1 KW = $2\times 1=2\ KW=2000\ W$

∴ Total power = $300+480+2000=2780\ W$

ii) Total energy consumed in one day = $8\times 2780=22240\ W=22.24\ KW$

iii) Energy consumed for the month of November,

   $22.24\times 30=667.2\ KW$

iv) Bill for the month of November if a unit of electricity costs Rs.26 is given as follows,

  cost = $667.2\times 26=17347.2 \ rupees$