Question

please solve the above problem...

Answer 1

let the original number be 10x +y
reversed never is 10y+x
sum of digits is x+y
ATQ,
x+y= 7 or y=7-x
10y+x=10x+y+27
9y=9x+22
9(7-x)=9x+27
63-9x=9x+27
36=18x
x= 2
so y = 7-x = 5
the number is 10(2)+5. =25


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Answer 2

Here is your answer:
Your answer is 25.