Please solve the above problem. Thanks in advance
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AB||EC
SO angleB+angle E=180
AngleE=180-60
AngleE=120
AngleBEC=angleFED opposite angles
In triangle DEF
AngleE +angleF+angle D=180
So 120+35+angleD=180
AngleD=180-155
AngleD=25
Ie angleCDF=25
SO angleB+angle E=180
AngleE=180-60
AngleE=120
AngleBEC=angleFED opposite angles
In triangle DEF
AngleE +angleF+angle D=180
So 120+35+angleD=180
AngleD=180-155
AngleD=25
Ie angleCDF=25
mirza66:
thank you
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