please solve the above problem. Thanks in advance
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Construction:Mark the transversal as M & N and Mark interacting point as A & T
Given: angleATN =105°
IF AB AND CD ARE PARALLEL LINES THEN angleATN=angleMSD=105°
3X+2X=105°
5X=105°
X=105°÷5
X=21°.
So,the value of X is 21°.
Given: angleATN =105°
IF AB AND CD ARE PARALLEL LINES THEN angleATN=angleMSD=105°
3X+2X=105°
5X=105°
X=105°÷5
X=21°.
So,the value of X is 21°.
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