Question

please solve the above question

Answer 1

Step-by-step explanation:

I hope it's Help you

by using exponential rules

Answer 2

$\: \: \: \: \frac{ {5}^{n + 3} - 6 \times {5}^{n + 1} }{9 \times {5}^{n} - {2}^{2} \times {5}^{n} } \\ = \frac{ {5}^{2} \times {5}^{n + 1} - 6 \times {5}^{n + 1} }{ {5}^{n}(9 - {2}^{2 } ) } \\ = \frac{ {5}^{n + 1} ( {5}^{2} - 6) }{ {5}^{n + 1 - 1}(9 - 4) } = \frac{( {5}^{n + 1})(25 - 6) }{( {5}^{n + 1})( {5}^{ - 1} )(5) } \\ = \frac{( {5}^{n + 1})(19) }{( {5}^{n + 1} )( {5}^{ - 1 + 1} ) } = \frac{19}{ {5}^{0} } = \frac{19}{1} \\ = 19$

$( {a}^{m} \times {a}^{n} = {a}^{m + n} )$

(anything to the power zero is 1)