please solve the above question
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First draw 2 normals BX and CY from B and C.
then according to mirror formula angle ABX=angle CBX and
angle BCY=angle DCY
Again,angle CBX=angle BCY
as BX and CY are parallel (both of them are normal from parallel sides PQ and RS)
now,angleCBX=angle BCY
so angle ABX=angle DCY
now angleCBX + angle ABX = angle BCY+angle DCY
so, angle ABC=angle BCD
NOW these two are alternate interior angle of AB and CD
so AB parallel to CD
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