Question

Please solve the above question ​

Answer 1

Answer:

I think second answer it is not correct but I gussed

Explanation:

plz tell which standard question it is

Answer 2

Explanation:

$\tt S + {O}_{2} \longrightarrow S{O}_{2} \:\:\:\: \Delta H = - 298.2 \:KJ \\ \\ \tt S{O}_{2} +\frac{1}{2} {O}_{2} \longrightarrow S{O}_{3} \:\:\:\: \Delta H = -98.7 \:KJ \\ \\ \tt S{O}_{3} + {H}_{2}O \longrightarrow {H}_{2}S{O}_{4} \:\:\:\: \Delta H = -130.2 KJ \\ \\ \tt {H}_{2} + \frac{1}{2}{O}_{2} \longrightarrow {H}_{2}O \:\:\:\: \Delta H =-227.3 KJ \\ \\ \tt The\:reaction\:for\:formation\:of\:{H}_{2}S{O}_{4} is \\ \\ \tt {H}_{2} + S + 2{O}_{2} \longrightarrow {H}_{2}S{O}_{4} \\ \\ \tt If\:we\:carefully\:observe\:the\:above\: reactions \: \\ \\ \tt The\:required\:reaction\:is\:obtained\:by\:adding\:above\:reactions \\ \\ \tt So\:the\:enthaply\:of\:formation \:of \:{H}_{2}S{O}_{4} \:is\: \\ \\ \Delta H = - ( 298.2 +98.7 + 130.2 + 227.3) \\ \\ \tt \longrightarrow \Delta H = - 754.4 \:kJ \\ \\ \boxed{\bold{\underline{\red{\tt \: The\: enthalpy\:of\: formation\:of\:{H}_{2}S{O}_{4} \:is \: - 754.4 \: kJ }}}}$