Chemistry, asked by sonu806, 1 year ago

please solve the above question fast

Attachments:

Jhampakia: 10.5

sonu806: kaise

Jhampakia: 80/100×10 + 15/100×12 + 5/100×14

Answers

Answered by sethuvamsikrishna

option is (1) for the given question

Answered by Juststudent1411

average atmoic mass = [mass of 1st isotope x its abundanse + mass of second x its abundance .. ..]/100

am=(10x 80+12x15+14x5)/100

am=10.5

hope u get it .. if u didnt u know what to do

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