Question

Please solve the above question for me.
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Answer 1

Step-by-step explanation:

(3^2)^x+1*(3^-x/2)^-2-(3^3)^x/(3^y*2)^3=1/729

(3^2x+2)*3^x-(3^3x)/3^3y=8/729

3^(2x+x+2)-3^3x/3^3y=8/729

3^3x+2-3^3x/3^3y=8/729

3^3x(3^2-1)/3^3y=8/729

3^3x*8/3^3y=8/729

3^3x/3^3y=1/729

3^3(x-y)=3^-6

3(x-y)=-6

x-y=-2

y-x=2