Question

Please solve the above question it is very urgent (Simple question)

Answer 1

Answer:

√2/4

Step-by-step explanation:

kindly check the attachment for the stepwise solution and answer.

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Answer 2

Given :

tanA = √2 - 1

To Find :

tanA/1 + tan^2A

Solution :

$\frac{tan \: a}{1 + tan^{2} a} \\ \\ = \frac{tan \: a}{sec^{2} a} \: \: \: \: (sec ^{2} a - {tan}^{2} a = 1) \\ \\ = tan \: a \times \frac{1}{ {tan}^{2} a} \\ \\ = \frac{1}{tan \: a}$

$= \frac{1}{ \sqrt2 - 1} \\ \\ = \frac{\sqrt{2} + 1 }{ (\sqrt{2} - 1) ( \sqrt{2} + 1)} \\ \\ = \frac{ \sqrt{2} + 1 }{2 - 1} \\ \\ = \sqrt{2} + 1$

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