please solve the above questions 16 17 18.
Answers
Answer:
16) a,b, d
17) a,b,c
18) b, d
Explanation:
16)
Known values :
Vo = velocity for both projection
H1 > H2
also ,
since , v and 2g are constant for both we can say that,
h is Directly proportional to sin(∅)
means if H1 > H2 , then. sin(∅1) > sin(∅2)
and ∅ is acute angle so ,
∅1 > ∅2
option a >> is true ( correct )
Now, Time of flight =
similarly , t directly varies with sin(∅) or ∅
So, T1 > T2 as ∅1 > ∅2
option b >> is true (correct)
Now, Range =
R directly varies with sin(2∅)
But ,note we know ,∅1 > ∅2 and
let ∅1 = 30° and ∅2 = 60°
so, sin(2× ∅1 ) = sin(2 × ∅2) = √3/2
Thus , R1 is not always greater than R2.
so option c >> is false ( incorrect)
Total energy = U = mgH + ½ mv²
AS , WE KNOW , H1 > H2 and m , v, g are constant
so U1 > U2
option d >> is true ( correct)
Now comes the question number 17
If a particle is performing uniform circular motion then,
1) Its speed remains constant throughout the motion.
2)Tangential acceleration is always zero.
3)The magnitude of the radial acceleration is constant always.
a) option is correct
Magnitude of particle velocity must remain constant .
b) option is correct
Particle velocity remains directed perpendicular to radius vector.
c) option is correct
direction of acceleration keeps changing as particle moves
d) option is incorrect
Now comes question number 18
we know ,
|A + B| = √{A² + B² + 2|A||B|cos∅}
|A - B| = √{A² + B² - 2|A||B|cos∅}
Now we can see that
| A + B | = | A - B| is possible if 2|A||B|cos∅ is 0
i.e. 2|A||B|cos∅ = 0
=> |A||B|cos∅ = 0
so, we can conclude that ,
Either,
=> cos∅ = 0
=> ∅ = π/2 which means |A| perpendicular |B|
Or,
=> |A| = 0 else |B| = 0
So, we can say that
option b and d are correct.
option a and c are incorrect.