PLEASE SOLVE THE ABOVE QUESTIONS
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Answer:
Lengths of the diagonals of a rhombus are 24 cm and 32 cm.
The perimeter of the rhombus = 4[12^2+16^2]^0.5
= 4[144+256]^0.5
= 4*20
= 80 cm.
Step-by-step explanation:
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diagonal of rhombus bisect each other at right angle.
1st side of triangle=base=12cm
2nd side of triangle=perpendicular=16cm
H^2=B^2+P^2
H^2=12^2+16^2
H^2=144+256
H^2=400
H=20cm
side of rhombus=20cm
Perimeter of rhombus=4×20
=80cm.
1st side of triangle=base=12cm
2nd side of triangle=perpendicular=16cm
H^2=B^2+P^2
H^2=12^2+16^2
H^2=144+256
H^2=400
H=20cm
side of rhombus=20cm
Perimeter of rhombus=4×20
=80cm.
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