Math, asked by samaddritasarkar2011, 2 months ago

please solve the answer​

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Answered by ramkrishnanj10
1

Answer:

 \frac{ \sqrt{5}( \sqrt{3} -  \sqrt{2}  }{ (\sqrt{3}  +  \sqrt{2})( \sqrt{3 } -  \sqrt{2)}   } =  \frac{ \sqrt{15} }{1}  \\  =  \sqrt{15 }  \\  -  \frac{3 \sqrt{3}( \sqrt{2}  -  \sqrt{5)}  }{ (\sqrt{2}  + \sqrt{5})( \sqrt{2} -  \sqrt{5} )  }  =  \frac{3 \sqrt{6 }  - 3 \sqrt{15} }{ - 3}  \\  =  - 1( \sqrt{6}  -  \sqrt{15}  \\  =  -  \sqrt{6}  +  \sqrt{15 }  \\   \\  \\  \frac{2 \sqrt{2}( \sqrt{5}  -  \sqrt{3}  )}{ (\sqrt{5} +  \sqrt{3} )( \sqrt{5}  -  \sqrt{3)}  }  \\  = 2 \sqrt{10}  - 2 \sqrt{6 }  \div 2 \\  =  \sqrt{10}  -  \sqrt{6 }  \\  \\  =  \sqrt{15}  -  \sqrt{6}   +  \sqrt{15}   +  \sqrt{10}  -  \sqrt{6 }  \\  = 2( \sqrt{15}  -  \sqrt{6} ) +  \sqrt{10}

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