Question

please solve the answer correctly....
maths question class 8 algebraic expressions and identities​

Answer 1

Step-by-step explanation:

Q6 : Add :-

1) ( 4a + 3b )²

Id.used = a² + 2ab + b² ;. a = 4 and b = 3

(4a + 3b) = (4a)² + 2(4)(3) + (3b)²

= 16a² + 24 + 9b²

Therefore, answer is 16a² + 24 + 9b²

2)

$( \frac{3}{2} x \: - \frac{2}{3} ) {}^{2}$

Id. used = a² - 2ab + b²

=

$(\frac{3}{2} )x {}^{2} - 2( \frac{3}{2} )( \frac{2}{3} ) + (\frac{2}{3} ) {}^{2}$

$\frac{6}{4} x {}^{2} - 2 + \frac{4}{6}$

( Sorry, but I know only of Q6, but I have written right answer )

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