please solve the answer I give and mark you as brainleist person and you are as to me as Einstein.
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The speed of the jet plane is 200 meters per second.
Given information in the question:-
- The angle of elevation is 60° in the first observation.
- After 15 seconds, the angle of elevation is 30°.
- The height of the jet plane is 1500√3 km.
The trigonometric ratio is a ratio of two sides in the right triangle. Let's first draw a diagram to understand the problem. (Attachment Ⅰ)
We know that,
So, using this,
So, the speed of the jet plane is 200 meters per second.
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Step-by-step explanation:
given :
- angle elevation from point A = 60 degree
- after a flight = 15 second
- angle elevation changes = 30 degree
- constant flying = 1500 √3
to find :
- speed of jet plane = ?
- speed of jet plane = ?
solution :
- jet plane flying the constant = 1500 √ 3
- Initially jet plane on A point after 15 second
- flight point B
- plane position after 15 sec
- ∆EBC from 30 degree = y/1500√3
- y/1500√3 = √3 ⇒ y = 1500 √3 x √3 = 4500
- ∆EDA from 60 degree = x/1500√3 = x/1500√3
- = 1/√3
- x= 1500
- Distance travelled in 15 seconds = (4500-1500) m = 3000 m.
- travelled in 1 second = 3000/15
- = 200 m
learn more :
- we will find in this question how much
- distance travelled
- and also find speed of jet finally
- we find in last distance
- so answer we will get
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