Question

Please solve the attached nd let me know ASAP please

Answer 1

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In fig. a)

No. of sides = 3

No. of Angles = 3

∠ABC = Right angle

∠BAC, ∠ACB = Acute Angle

In fig. b)

No. of sides = 4

No. of angles = 4

∠PMN = Acute angle

∠PON, ∠MNO = Right angle

∠OPM = Obtuse angle

In fig. c)

No. of sides = 5

No. of angles = 5

∠PQR, ∠PTS = Obtuse angle

∠QRS, ∠RST = Right angle

∠TPQ = Acute angle

In fig. d)

No.of sides = 5

No. of angles = 5

∠EFG, ∠FGH, ∠GHI = Obtuse angle

∠EIH = Acute angle

∠IEF = Right angle

Thanks❤️

Answer 2

Answer:

a) Acute angles -> angle ACB & angle BAC, Obtuse angles -> 0

b) No. of sides -> 4; No. of angles -> 4; Right angles -> angle NOP, angle MNO; Acute angles -> angle PMO; Obtuse angles -> angle OPM

c) No. of sides -> 5; No. of angles -> 5; Right angles -> angle QRS, angle RST, angle TPQ; Acute angles -> 0; Obtuse angles -> angle PQR, angle STP

d) No. of sides -> 5; No. of angles -> 5; Right angles -> angle IEF; Acute angles -> angle HIE; Obtuse angles -> angle EFG, angle FGH, angle GHI

Hope this helps you