Question

Please solve the attached problem ​

Answer 1

Answer:

Given: AC=3 cm, BC=4 cm

In ΔABC,

(AC)

2

+(BC)

2

=(AB)

2

3

2

+4

2

=(AB)

2

9+16=(AB)

2

(AB)

2

=25

AB=5 cm

Area of shaded region = Area of semicircle or side AB− Area of ΔABC

=

2

πr

2

−

2

1

×AC×BC

=

7

22

×

2

2.5

2

−

2

1

×3×4 (Where r=

2

AB

=

2

5

=2.5)

= 9.821−6

=3.821

So, the area of the shaded region is 3.821 cm

2