please solve the attached question
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Step-by-step explanation:
Draw line ED parallel to line BC. (Construction)
So now we have A-E-B and A-D-C.
Mark the point if intersection of line DB and EC as 'o'.
∠BEO ≅ ∠CDO (As both the angles are 90°)
∠EBO ≅ ∠DOC
side BE ≅ side DC (Because ED is parallel to BC)
Therefore BD = CE (By AAS test )
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You can solve like this....
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