Question

please solve the attached question
I will mark brainliest who will answer​ correctly​

Answer 1

In the given figure we have a circle inscribed in triangle.

Using (1), we have

From point A , AD=AF (a)

From point B , BD=BE (b)

From point C , EC=CF (c)

Given : AB=AC (i)

Also, AB=AD+BD and AC= AF+CF (ii)

From (i) and (ii)

AD+BD=AF+CF

Using (a), we get BD=CF (iii)

From (b), (c) and (iii)

BD=BE=CF=EC

⇒BE=EC

Hence Proved.

Answer 2

Answer:

From point A , AD=AF (a)

From point B , BD=BE (b)

From point C , EC=CF (c)

Given : AB=AC (i)

Also, AB=AD+BD and AC= AF+CF (ii)

From (i) and (ii)

AD+BD=AF+CF

Using (a), we get BD=CF (iii)

From (b), (c) and (iii)

BD=BE=CF=EC

⇒BE=EC

hence  it is proved

Step-by-step explanation:

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