Please solve the attachment!!
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Step-by-step explanation:
Solution :-
Given that
The length of the rectangle (l) = (X+7) cm
Let the width be b cm
We know that
Area of a rectangle = lb sq.units
Area of the given rectangle = (X²+5X-14) cm²
=> (X+7)×b = X²+5X-14
=> b = (X²+5X-14)/(X+7)
=> b = (X²+7X-2X-14)/(X+7)
=> b = [X(X+7)-2(X+7)]/(X+7)
=> b = (X+7)(X-2)/(X+7)
=> b = (X-2) cm
Therefore, width = (X-2) cm
41.
Find the width of the rectangle
42.
The length of the rectangle is (X+7) cm and Area of the given rectangle is (X²+5X-14) cm²
43.
The working equation is (X+7)×b = X²+5X-14
44.
(X+7)×b = X²+5X-14
=> b = (X²+5X-14)/(X+7)
=> b = (X²+7X-2X-14)/(X+7)
=> b = [X(X+7)-2(X+7)]/(X+7)
=> b = (X+7)(X-2)/(X+7)
=> b = (X-2) cm
45.
The answer is (X-2) cm
Used formulae:-
→ Area of a rectangle = lb sq.units
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