Question

please solve the attachment..​

Answer 1

Step-by-step explanation:

Given :-

a = 2

b = 3

To find :-

i) a^a + b^b

ii) a^b + b^a

iii) a^b

iv) (a/b)^a

v) [(1/a)+(1/b)]^a

Solution :-

Given that

a = 2

a = 2b = 3

i) The value of a^a + b^b

=> 2²+3³

=> (2×2)+(3×3)

=> 4+9

=> 13

Therefore, a^a + b^b = 13

ii) The value of a^b + b^a

=> 2³+3²

=> (2×2×2)+(3×3)

=> 8+9

=> 17

Therefore, a^b + b^a = 17

iii) The value of a^b

= 2³

= (2×2×2)

= 8

Therefore, a^b = 8

iv) The value of (a/b)^a

= (2/3)²

= (2/3)×(2/3)

= (2×2)/(3×3)

= 4/9

Therefore, (a/b)^a = 4/9

v) The value of [(1/a)+(1/b)]^a

=> [(1/2)+(1/3)]²

LCM of 2 and 3 = 6

=> [(3+2)/6]²

=> (5/6)²

=> (5/6)×(5/6)

=> (5×5)/(6×6)

=> 25/36

Therefore, [(1/a)+(1/b)]^a = 25/36

Answer :-

i) a^a + b^b = 13

ii) a^b + b^a = 17

iii) a^b = 8

iv) (a/b)^a = 4/9

v) [(1/a)+(1/b)]^a = 25/36

Answer 2

Step-by-step explanation:

please check the above picture..