Accountancy, asked by Nancyvats, 1 year ago

Please solve the attachment..

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Answered by SnehaG50
2
\mathbb{\orange{\huge{Hello\:Nancy}}}

Radius of well = 5m
depth = 14m
volume of Earth taken out =πr^2h
=π×(5)^2×14=1100m2

now , it is spread to form embankment which is the form of hollow cylinder.
inner radius ,r=5m
outer radius= 57.5
height
then ,1100=π×h(10^2-5^2)
h=350/75=14/3=4.67m
Answered by ans81
0
radius of well = 5 m
depth = 14 m
volume of earth taken out = πr² h = π×(5)²×14= 1100 m³
now, it is spread to form embankment, which is in the form of hollow cylinder,
inner radius, r= 5 m
outer radius = 5 +5 = 10 m
height= h
then, 1100 = π×h(10²- 5²)
⇒h = 350/75 = 14/3 = 4.67 m
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