Math, asked by Anonymous, 5 hours ago

Please solve the attachment!!!

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Answered by Anonymous
18

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➬ In adjoining figure name the following pair of angles :

  • obtuse vertically opposite angles
  • Equal supplementary angles
  • Adjacent angles that do not form a linear pair
  • Adjacent complementary angles

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  • Obtuse vertically opposite angles

➬ ∠ AOD and ∠BOC form obtuse vertically opposite angles

  • Equal supplementary angles

➬∠EOB and ∠EOD form

Equal supplementary angles

  • Adjacent angles that do not form a linear pair

➬(∠AOB ,∠AOE)

➬(∠AOE ,∠EOD)

➬(∠EOD ,∠COD) are all Adjacent angles pairs that do not form a linear pair

  • Adjacent complementary angles

➬(∠EOA ,∠AOB) form Adjacent complementary angles

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➬ Identify the like term in following :

➬ -xy²,4yx²,20x²y,-100x

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❒ In the given terms ,The like term are grouped as under :

4yx²,20x²y is like term

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➬ Show terms and factors by Tree diagram

5xy+7x²y

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Refer the attachment

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➬Subtract vertically

  • 24 ab -10 b-18 a from 30 ab+12b+14 a

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➬ 30 ab+12b+14 a -

➬ 24 ab -10 b-18

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30 ab+12b+14 a

24 ab -10 b-18

(-) (+) (+)

____________

6ab +22b+32 a

❒ Therefore

6ab +22b+32 a is required answer

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\large\underline{\underline{\maltese{\color{darkblue}{\pmb{\sf{\: Question -5 :-}}}}}}

➬ The value of expression

5n²+5n -2 and when n = -2

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5n²+5n -2 when n = -2

➬( Putting n = -2 )

5 × (-2)+ 5 × (-2) -2

5 × 4 - 10 -2

20 - 12

8

❒ Therefore

8 is required answer

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Answered by MasterDhruva
18

Answer (A7) :-

1. Obtuse vertically opposite angles

  • ∠BOC and ∠AOE + ∠EOD

2. Equal supplementary angles

  • ∠EOB and ∠EOD

3. Adjacent angles that do not form linear pair

  • ∠DOE and ∠AOE

4. Adjacent complementary angles

  • ∠BOA and ∠BOE

Answer (A8)a :-

 \sf \longrightarrow { - xy}^{2} , {4yx}^{2} , {20x}^{2}y , - 100x

The like term in the set of expressions are,

 \sf \longrightarrow {4yx}^{2} \: and \: {20x}^{2}y

[Answer of (A8)b is attached]

Answer (A9) :-

 \sf \longrightarrow 30ab + 12b + 14a - (24ab - 10b - 18a)

 \sf \longrightarrow 30ab + 12b + 14a - 24ab + 10b + 18a

 \sf \longrightarrow 30ab - 24ab + 12b + 10b + 14a + 18a

 \sf \longrightarrow 6ab + 22b + 32a

Answer (A10) :-

 \sf \longrightarrow {5n}^{2} + 5n - 2

We know that, n = -2. So,

 \sf \longrightarrow 5({-2}^{2}) + 5( - 2) - 2

 \sf \longrightarrow 5(4) + ( - 10) - 2

 \sf \longrightarrow 20 - 10 - 2

 \sf \longrightarrow 8

Hence solved !!

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