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Answered by dt6201642
0

Step-by-step explanation:

take- graph paper : the mathmatics classes - 10 th is chapter -2

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Answered by mathdude500
4

\large\underline{\sf{Solution-}}

Given Coordinates are

  • O (0, 0)

  • A (- 4, 4)

  • B ( - 3, 0)

  • C ( 0, - 3 )

Now, we know that,

When any coordinate P (x, y) is reflected in y-axis, then the image P' is formed in the second quadrant whose co-ordinates are (- x, y).

Thus, from this we concluded that when a point is reflected in y-axis, then the y-co-ordinate remains the same and we have to change the sign of x - co-ordinate.

Thus, the image of P (x, y) is P' (-x, y).

Now, Reflection of A (- 4, 4) under y - axis is A' (4, 4)

Reflection of B ( - 3, 0 ) under y - axis is B' ( 3, 0 )

The figure thus obtained OABCB'A'

Having line of symmetry along y - axis.

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Additional Information

Rules to find the reflection of a coordinate in the x-axis:

(i) Same sign of the abscissa i.e., x-coordinate.

(ii) Change the sign of the ordinate i.e., y-coordinate.

Rules to find the reflection of a point in the y-axis:

(i) Change the sign of abscissa i.e., x-coordinate.

(ii) same sign of the ordinate i.e., y-coordinate.

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