Please solve the below questions. i just need the answer no matter what you use (like paper, typing etc..) just dont type rubbish 'cause i'll report them. :)
Answers
Answer:
3) Number = 27
4) Number = 12
Step-by-step explanation:
3) Let the digits of the number = x, y
Given that x + y = 9 _____(1)
Number = 10x + y (the algebraic form of any two digit number is 10x+y)
Number got by reversing the digits = 10y+x
Given that, 3(10x+y)-9 = 10y+x
30x+3y-9 = 10y+x
30x - x - 9 = 10y - 3y
29x - 9 = 7y
ie, 29x - 7y = 9 _____(2)
(2) + (1) = (29x - 7y) + (x + y) = 9 - 9
Multiply (1) by 7 to get the same number with coefficient y in (2)
ie, (29x - 7y) + (7x + 7y) = (7 × 9)+9 = 63 + 9
36x = 72
x = 72 ÷ 36 = 2
Substituting the value of x in (1), we get,
2 + y = 9
y = 9 - 2 = 7
Therefore the number = 27
4) Let the digits = x, y
Sum of digits = x + y = 3 ____(1)
Number = 10x + y
Number got by reversing the digits = 10y+x
Given that, 7(10x+y) = 4(10y+x)
70x + 7y = 40y + 4x
70x - 4x = 40y - 7y
66x = 33y
2x = y (dividing by 33)
x = y/2 _____(2)
Substituting the value of x in (1), we get,
(y/2)+y = 3
(y/2)+(2y/2) = 3
(3y)/2 = 3
3y = 3 × 2 = 6
y = 6 ÷ 3 = 2
Substituting the value of y in (1), we get,
x + 2 = 3
x = 3 - 2 = 1
Therefore the Number = 12
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