Math, asked by Sameerriaz, 1 year ago

please solve the equation​

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Answered by dangerousqueen01
2

Step-by-step explanation:

 \frac{3}{2} (2x - 1) =  \frac{1}{2}  +  \frac{7x}{8}  \\  =  >  \frac{3(2x - 1)}{2}  =  \frac{1}{2}  +  \frac{7x}{8}  \\  =  >  \frac{(6x - 3)}{2}  =  \frac{(4 + 7x)}{8}  \\  =  > 8(6x - 3) = 2(4 + 7x) \\  =  > 48x - 24 = 8 + 14x \\  =  > 48x - 14x = 8 + 24 \\  =  > 34x = 32 \\  =  > x =  \frac{32}{34}  \\  =  > x =  \frac{16}{17}

Answered by Anonymous
1

 \huge{ \underline{ \bold{ᴀɴsᴡᴇʀ....{ \heartsuit}}}}

$$\begin{lgathered}\frac{3}{2} (2x - 1) = \frac{1}{2} + \frac{7x}{8} \\ = > \frac{3(2x - 1)}{2} = \frac{1}{2} + \frac{7x}{8} \\ = > \frac{(6x - 3)}{2} = \frac{(4 + 7x)}{8} \\ = > 8(6x - 3) = 2(4 + 7x) \\ = > 48x - 24 = 8 + 14x \\ = > 48x - 14x = 8 + 24 \\ = > 34x = 32 \\ = > x = \frac{32}{34} \\ = > x = \frac{16}{17}\end{lgathered}$$

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