Math, asked by akshat5755, 1 year ago

please solve the equation

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Answered by MOSFET01
11

\bold{\large{\underline{Solution}}}


\bold{\large{ Q1 \:\: \: \dfrac{\Bigg(\dfrac{3}{4}x \: + \: 1 \Bigg)}{\Bigg(x \: + \: \dfrac{1}{5}\Bigg)}\: = \: \dfrac{7}{4}}}


\bold{\large{\implies \dfrac{\Bigg(\dfrac{3x\: + \: 4}{4}\Bigg)}{\Bigg(\dfrac{5x\:+\:1}{5}\Bigg)} \: = \: \dfrac{7}{4} }}


\bold{\large{\implies \dfrac{3x\: + \: 4}{4} \times \dfrac{5}{5x\: + \: 1} \: = \: \dfrac{7}{4}}}


\bold{\large{\implies \dfrac{15x \: + \: 20}{5x\: + \: 1} \: = \: 7}}


\bold{\large{\implies 15x \: + \: 20 \: = \: 35x \: + \: 7}}


\bold{\large{\implies 35x\: + \: 7 \: = \: 15x \: + \: 20}}


\bold{\large{\implies 35x \: -\: 15x \: = \: 20\: - \: 7 }}


\bold{\large{\implies 20x \: = \: 13 }}


\bold{\large{\implies  x \: = \: \dfrac{13}{20}}}


\bold{\large{\underline{Answer}}}


\bold{\large{\boxed{\boxed{ x \: = \: \dfrac{13}{20}}}}}


\bold{\large{\underline{Thanks}}}





Steph0303: Perfect :)
MOSFET01: Welcome :)
Answered by Anonymous
0
ANSWER IS 13/20
NICE........
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