Question

please solve the equation

Answer 1

$\frac{(x + 1)(4x - 3) - {4x}^{2} + 5 }{4x + 1} = 2 \\ \frac{ {4x}^{2} - 3x + 4x - 3 - {4x}^{2} + 5 }{4x + 1} = 2 \\ \frac{ {4x}^{2} - {4x}^{2} - 3x + 4x - 3 + 5 }{4x + 1} = 2 \\ -3x + 4x - 3 + 5 = 2(4x + 1) \\ x + 2 = 8x + 2 \\ 2 - 2 = 8x - x \\ 0 = 7x \\ 7x = 0 \\ x = \frac{0}{7} \\ x = 0 \\ mark \: as \: brainliest$