Question

please solve the equation with steps ...........wrong answer will be reported.​

Answer 1

cosA=5/13

sinA=-√(1-cos^2A) (since theta is in 4th quadrant)

i.e. sinA=-√144/169

=-12/13

tanB=-15/8

sinB=+(15)/√{(-15)^2+(8)^2} (B is in Q2)

i.e. sinB=15/17

cosB=tanB/sinB

i.e. cosB=-15/8 * 17/15

cosB=17/8

now

sin(A+B)=sinAcosB+cosAsinB

sin(A+B)=(-12/13)(17/8)+(5/13)(15/17)

={1/13}(-51/2 + 75/17)

=(1/13)(-710/34)

=-710/442

Answer 2

Answer:

$\huge\bold\pink\star\underline\red{ANSWER :-}$

Step-by-step explanation:

$\frac{3x - 1}{4} - \frac{x - 1}{2} = 0$

$\frac{3x - 1}{4} = \frac{x - 1}{2}$

$= > 2(3x - 1) = 4(x - 1)$

$= > 6x - 2 = 4x - 4$

$= > 2x = 2 = > x = 1ans.$