Question

please solve the example 2 more fast and easily...​

Answer 1

Answer: Have a look at the picture:

Step-by-step explanation:

Answer 2

hi,

sinB=AC/AB

sinQ=PR/PQ

AC/AB=PR/PQ

then by cross multiplying we get,

AC/PR=AB/PQ

which is equal to 'm'. - equ 1

by using pythagoras theorem, we can state that

BC=√AB²-AC²

and

QR=√PQ²-PR²

so, we can say that,

BC/QR = √AB²-AC²/ √PQ²-PR²

which is equal to

= √m²PQ²-m²PR²/ √PQ²-PR²

= m √PQ²-PR²/ √PQ²-PR² = m. -equ 2

from 1and 2 we have

AC/PR= AB/PQ= BC/QR

therefore, by stating the theorem:

if any two triangles, side of one triangle are proportional to the sides of the other triangle, then their corresponding angles are equal and hence the two triangles are similar.

= triangle ABC ~ triangle PQR

therefore angles B and Q are equal.

hope this helps you