Question

Please solve the following

Answer 1

$\large\bf{\underbrace{\red{SOLUTION:-}}}$

(iii) ✴️ Part ‘OB’ of the graph represent uniform acceleration .

✴️ And Part ‘BC’ of the graph represent uniform retardation .

(iv) We have know that, slope of Velocity-time graph gives acceleration .

✴️ So, At t = 0s , u = 0 m/s

At t = 2s , v = 10 m/s

$\bigstar\:\rm{\purple{\boxed{a\:=\:\dfrac{v\:-\:u}{t}\:}}}$

• u = initial velocity
• v = final velocity
• t = time

$\rm{\implies\:a\:=\:\dfrac{10\:-\:0}{2}\:}$

$\rm{\boxed{\implies\:a\:=\:5\:m/s^2\:}}$

Answer 2

★ $\large\underline\mathrm\red{Solution :-}$

(iii) Which parts of the graph represents uniform acceleration and uniform retardation ?

→ In the graph, OB represent uniform acceleration .

→ BC represent uniform retardation .

(iv) Calculate acceleration .

→ Acceleration is given by slope of velocity time graph i.e. v - t graph.

• Here, At t = 0 sec , u= 0 m/s
• At t = 2 sec , v = 10 m/s .

$We \: know \: that → a \frac {v - u}{t}$

Here,

• u = initial velocity
• v = final velocity
• t = time taken

$a = \frac {10-0}{2}$

$\boxed{→ a = 5 m/s²}$