Math, asked by Sonikaaaa, 6 hours ago

please solve the following

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Answered by robelyndemafiles05
0

Answer:

Hey there!

\begin{gathered} {8a}^{3} - {b}^{3} - 12 {a}^{2} b + 6a {b}^{2} \\ \\ = ( {2a})^{3} + ( { - b})^{3} + 3(2a) ( - b) (2 a - b) \\ \\ = (2a - b) ^{3} \\ \\ = (2a - b)(2a - b)(2a - b) \\ \\ \end{gathered}

8a

3

−b

3

−12a

2

b+6ab

2

=(2a)

3

+(−b)

3

+3(2a)(−b)(2a−b)

=(2a−b)

3

=(2a−b)(2a−b)(2a−b)

\begin{gathered} \textsf{formulae} \\ \\ {(a - b)}^{3} = { a}^{3} - {b}^{3} - 3ab(a - b) \\ \\ \end{gathered}

formulae

(a−b)

3

=a

3

−b

3

−3ab(a−b)

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