please solve the following
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\begin{gathered} {8a}^{3} - {b}^{3} - 12 {a}^{2} b + 6a {b}^{2} \\ \\ = ( {2a})^{3} + ( { - b})^{3} + 3(2a) ( - b) (2 a - b) \\ \\ = (2a - b) ^{3} \\ \\ = (2a - b)(2a - b)(2a - b) \\ \\ \end{gathered}
8a
3
−b
3
−12a
2
b+6ab
2
=(2a)
3
+(−b)
3
+3(2a)(−b)(2a−b)
=(2a−b)
3
=(2a−b)(2a−b)(2a−b)
\begin{gathered} \textsf{formulae} \\ \\ {(a - b)}^{3} = { a}^{3} - {b}^{3} - 3ab(a - b) \\ \\ \end{gathered}
formulae
(a−b)
3
=a
3
−b
3
−3ab(a−b)
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