Question

Please solve the following creative question (c) no.



plz answer me fast...............





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Answer 1

Answer:

Can you write it in English

Answer 2

Step-by-step explanation:

$x - \frac{1}{x} = \sqrt{3} \\ \frac{ {x}^{2} - 1}{x} = \sqrt{3} \\ {x}^{2} - 1 = \sqrt{3}x \\ {x}^{2} - \sqrt{3} x = 1.$

$x - \frac{1}{x} = \sqrt{3} \\ (x - \frac{1}{x} ) {}^{2} = 3 \\ {x}^{2} + \frac{1}{ {x}^{2} } - 2 = 3 \\ {x}^{2} + \frac{1}{ {x}^{2} } = 5 \\ ( {x}^{2} + \frac{1}{ {x}^{2} } ) {}^{2} = 25 \\ {x}^{4} + \frac{1}{ {x}^{4} } + 2 = 25 \\ {x}^{4} + \frac{1}{ {x}^{4} } = 23 \\ ( {x}^{2} + \frac{1}{ {x}^{2} } )( {x}^{4} + \frac{1}{ {x}^{4} } ) = 23( {x}^{2} + \frac{1}{ {x}^{2} } ) \\ 5( {x}^{4} + \frac{1}{ {x}^{4} } ) = 23( {x}^{2} + \frac{1}{ {x}^{2} } )$

${x}^{2} + \frac{1}{ {x}^{2} } = 5 \\ ( {x}^{2} + \frac{1}{ {x}^{2} } ) ^{3} = {5}^{3} \\ {x}^{6} + \frac{1}{ {x}^{6} } + 3. {x}^{2} . \frac{1}{ {x}^{2} } ( {x}^{2} + \frac{1}{ {x}^{2} } ) = 125 \\ {x}^{6} + \frac{1}{ {x}^{6} } + 3 \times 5 = 125 \\ {x}^{6} + \frac{1}{ {x}^{6} } = 125 - 15 \\ {x}^{6} + \frac{1}{ {x}^{6} } = 110.$