Question

Please solve the following equation !!

The age of a father 10 years ago was three times the age of his son. The sum of their present ages is 80 years. Find their present ages. ​

Answer 1

⭐⭐⭐HI your answer is attached in the picture ⭐⭐⭐

Answer 2

Answer

y−10=3(x−10)

⇒y−10=3x−30

⇒y=3x−30+10

⇒y=3x−20

y+10=2(x+10)

⇒y+10=2x+20

⇒y=2x+20−10

⇒y=2x+10  

3x−20=2x+10

⇒3x−2x=10+20

⇒x=30

30

70

​

=  

3

7

​

=7:3