please solve the following exponent:
3^-5×3^2÷3^-6+(2^2×3)^2+[2/3]^-1+2^-1+[1/19]^-1
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Answered by
1
Answer:
Step-by-step explanation:
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Answered by
0
Answer:
Let us simplify,
3
−5
×3
2
÷3
−6
+(2
2
×3)
2
+(
3
2
)
−1
+2
−1
+(
19
1
)
−1
=3
−5
×3
2
×3
6
+(2
2
×3)
2
+(
3
2
)
−1
+2
−1
+(
19
1
)
−1
[∵a÷b=a×b
−1
]
=3
−5+2+6
+(2
4
×3
2
)+
2
3
+
2
1
+19
1
[∵a
m
×a
n
=a
m+n
and (
b
a
)
−1
=
a
b
]
=3
3
+(16×9)+
2
4
+19
=27+144+2+19
=192
Step-by-step explanation:
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