Math, asked by angelina1495, 1 month ago

Please solve the following problem……………………

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Answers

Answered by dheekshagouri
1

Step-by-step explanation:

1)(6a³-2a)/2a

Now

we can take 2a common from numerator

⇒2a(3a²-1)/2a

⇒(3a²-1)

3) (6a²b-9ab²)/(3ab/2)

Now

we can take 3ab common from numerator

⇒3ab(2a-3b)/(3ab/2)

⇒2(2a-3b)

⇒(4a-6b)

Answered by Marichat11
2

1 = 3a^2 -1

2= -4a^2-1

3=4a^3-6a^2b^3

4= xy+y^2-1

hope it would help you.

Have a nice day

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