Please solve the following question
Sides of the Pentagon are produced.
Find the sum of angle 1,2,3,4 and 5
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Answer:
180°
Step-by-step explanation:
Let a, b, c, d, e be the interior angles of the pentagon as in the diagram.
Also, let x and y be the two other angles in the triangle with ∠1, as in the diagram.
∠1 = 180° - x - y
= ( 180° - x ) + ( 180° - y ) - 180°
= a + b - 180°
Similarly:
∠2 = b + c - 180°, ∠3 = c + d - 180°,
∠4 = d + e - 180°, ∠5 = e + a - 180°
So
∠1 + ∠2 + ∠3 + ∠4 + ∠5
= 2 ( a + b + c + d + e ) - 5×180°
The sum of the interior angles of a polygon with n sides is (n-2)×180°, so for a pentagon with n=5 sides, we have
a + b + c + d + e = 3×180°
Therefore
∠1 + ∠2 + ∠3 + ∠4 + ∠5
= 2 ( a + b + c + d + e ) - 5×180°
= 6×180° - 5×180°
= 180°
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