Question

please solve the following
$10 {c }^{2} - 3c - 1 = 0$


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Answer 1

Answer:

10c²-3c-1=0

10c²-5c+2c-1=0

5c(2c-1)+(2c-1)=0

(5c+1)(2c-1)=0

hope it helps..!!

Answer 2

$\huge \mathscr{\orange {\underline{\pink{\underline {✿Answer✿:-}}}}}$

10c² - 3c - 1 = 0

10c² - 5c + 2c - 1 = 0

5c( 2c - 1 )+( 2c - 1 ) = 0

( 5c + 1 )( 2c - 1 ) = 0.

• I Hope it's Helpful •