Please solve the four number question
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Let the first number = a
Let the second number = b
Let the third number= c
According to question :
Case 1 :
a × b = 28
Case 2 :
b × c = 77
Case 3 :
a × c = 44
a × b = 77 (Given)
a = 77/b ...(1)
a × c = 44 (Given)
a = 44/c ...(2)
from (1) and (2)
77/b = 44/c
77c = 44b
b/c = 44/77
b/c = 4/7
Therefore b = 4 and c = 7
put the value of b in equation (1)
a = 44/b = 44/4 = 11
Hence
The first number = a = 11
The second number = b = 4
The third number= c = 7
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