Question

Please solve the fourth question of que 2 step by step please mujhe samajh nhi aa rha​

Answer 1

Answer:

$\frac{2\sqrt{2} q^4 + 4\sqrt{2} q^3 + q^2 }{(-2\sqrt{2} q^2)}$  $=-q^2 - 2q - \frac{1}{2\sqrt{2}}$

Step-by-step explanation:

$\frac{2\sqrt{2} q^4 + 4\sqrt{2} q^3 + q^2 }{(-2\sqrt{2} q^2)}$

$=\frac{2\sqrt{2} q^4}{(-2\sqrt{2} q^2)} + \frac{4\sqrt{2} q^3}{(-2\sqrt{2} q^2)} + \frac{q^2}{(-2\sqrt{2} q^2)}$

$=-q^2 - 2q - \frac{1}{2\sqrt{2}}$

Answer 2

Step-by-step explanation:

iv) 2√2q⁴+4√2q³+q²/(-2√2q²)

=2√2q²(q²+2q+[1/2√2])/(-2√2q²)

= -(q²+2q+[1/2√2])

= -q²-2q-1/2√2