Physics, asked by Anonymous, 9 hours ago

Please solve the given question​

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Answered by ankitakenganur555
0

Answer:

let's first calculate the total resistance of CD=

the resistance of 3 resistors connected in parallel is:

r"=1/4+1/6+1/12

=3+2+1/12

=6/12

=1/2 Ω

the resistance of the 3 resistors connected in series is:

r'=1+3+1/2

=2+6+1/2

=9/2 Ω

now, let's calculate the total resistance of ef =

the resistance of 2 resistors connected in parallel is:

R"=1/5+1/20

=4+1/20

=5/20

=1/4 Ω

the resistance of the 2 resistors connected in series is:

R'=2+1/4

=8+1/4

=9/4Ω

Explanation:

the equivalent resistance=r'+R'

R=9/2+9/4

=18+9/4

=27/4

=6.75Ω.

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