Question

please solve the (iv)part​

Answer 1

Answer:

$(x + 1) = 0 \\ x = - 1 \\ put \: these \: value \: in \: the \: above \: eqns \\ then \: \\ \: (i) \: {x}^{3} + {x}^{2} + x + 1 \\ { - 1}^{3} + { - 1}^{2} + - 1 + 1 \\ = 0 \\ hence \: (x + 1) \: is \: a \: solution$

2,3,4 are not polynomials which have x plus one as factor

Answer 2

Answer:

(x+1) is the answer ☺️