please solve the problem
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for a triangle angles a+ b+c=180
dividing by 2
a/2 +b/2 +c/2=90
b/2+c/2=90- a/2
taking sin on both sides
sin(b+c/2)=sin(90-a/2)
sin(b+c/2)=cosa/2
because sin(90-theta)=cos theta
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sorry I don't know i will answer next time
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