Question

please solve the problem​

Answer 1

a4 = 10a

» a + ( 4 - 1 )d = 10a

» 3d = 9a

» d = 3a

To prove ,

a6 = 4a2

Therefore ,

a + ( 6 - 1 )3a = a + (4 - 1)3a

a + 15a = a + 9a

15a - 9a = 0

6a = 0

a = 0

Answer »» a = 0