Question

Please solve the problem

Answer 1

Answer:

this will result in an irrational no. because of root 2

Answer 2

Answer:

$3 \sqrt{2} {x}^{2} - 5x - \sqrt{2} = 0 \\3 \sqrt{2} {x}^{2} - 3x - 2x - \sqrt{2} = 0 \\ 3x( \sqrt{2} x - 1) - \sqrt{2} ( \sqrt{2} x - 1) = 0 \\ ( \sqrt{2} x - 1)(3x - \sqrt{2} \ ) = 0 \\ x = \frac{1}{ \sqrt{2} } \: or \: \frac{ \sqrt{2} }{3}$