Question

please solve the problem​

Answer 1

Hello, Buddy!!

Refer The Attachment ⤴️

• Value of x ➪ 2q-p

@MrMonarque♡

Hope It Helps You ✌️

Answer 2

QUESTION :- Solve for x

$\sf{\frac{x - q}{p + q} = \frac{x + q}{p - q}}$

SOLUTION :-

$\sf{→\frac{x - q}{p + q} = \frac{x + q}{p - q}}$

Cross multiplying the terms,

$\sf{→(x - q)(p - q) = (x + q)(p + q)}$

$\sf{→px - qx - qp + {q}^{2} = px + pq + qx + {q}^{2} }$

Canceling out the terms,

$\sf{→ \cancel{px} - qx - qp + \cancel{q}^{2} = \cancel{px} + pq + qx + \cancel{q}^{2}}$

$\sf{→- qx - qp = pq + qx}$

Bringing RHS to LHS,

$\sf{→- qx - qp - (pq + qx)} = 0$

$\sf{→- qx - qp - pq - qx} = 0$

$\sf{→ - 2qx - 2pq = 0}$

Taking -2q as common factor,

$\sf{→ - 2q(x + p) = 0}$

$\sf{→(x + p) = 2q}$

$\sf \fbox \green{→x = 2q - p}$

$\therefore$ Value of $\sf{x = 2q - p}$.