please solve the problem
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we can write cos A as sinA/cosA
=>(cosA/1+sinA )+(sinA/cosA)
=> (cos^2A+sin^2A+sinA)/(1+sinA)cosA
we know that sin^2A+cos^2A=1
=>(1+sinA)/(1+sinA)cosA
1+sinA is cancelled
we get 1/cosA=secA
hence proved
i hope u can understand.
=>(cosA/1+sinA )+(sinA/cosA)
=> (cos^2A+sin^2A+sinA)/(1+sinA)cosA
we know that sin^2A+cos^2A=1
=>(1+sinA)/(1+sinA)cosA
1+sinA is cancelled
we get 1/cosA=secA
hence proved
i hope u can understand.
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